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a. Suppose architecture A has 14-bit address bus. What is maximum size of memory that can be accessed in this architecture? (Show the steps for calculating maximum accessible memory)
Weegy: The maximum amount of memory usable by the instance is determined at instance startup by the initialization parameter SGA_MAX_SIZE. [ You can specify SGA_MAX_SIZE to be larger than the sum of all of the memory components, such as buffer cache and shared pool. Otherwise, SGA_MAX_SIZE defaults to the actual size used by those components. Setting SGA_MAX_SIZE larger than the sum of memory used by all of the components lets you dynamically increase a cache size without needing to decrease the size of another cache. ] (More)
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Asked 10/27/2011 3:16:06 AM
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An architecture B has a maximum limit of 2GB memory. How many address bits are required for this architecture? (Show the steps for calculating required number of address bits)
Weegy: 31 bits are required for this architecture. 2^31=2,147,483,648 (More)
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Asked 10/29/2011 1:11:27 AM
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Suppose architecture A has 14-bit address bus. What is maximum size of memory that can be accessed in this architecture? (Show the steps for calculating maximum accessible memory)
Weegy: 16384 memory elements, which is 2^14. (In typical modern usage, a "memory element" is an 8-bit byte, but there have certainly been exceptions to that in the past).31 bits are required for this architecture. 2^31=2,147,483,648 User: Suppose architecture A has 14-bit address bus. What is maximum size of memory that can be accessed in this architecture? (Show the steps for calculating maximum accessible memory) Weegy: 31 bits are required for this architecture. 2^31=2,147,483,648 (More)
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Expert Answered
Asked 10/29/2011 1:42:58 AM
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Suppose architecture A has 14-bit address bus. What is maximum size of memory that can be accessed in this architecture? (Show the steps for calculating maximum accessible memory)
Weegy: 16384 memory elements, which is 2^14. (In typical modern usage, a "memory element" is an 8-bit byte, but there have certainly been exceptions to that in the past).31 bits are required for this architecture. 2^31=2,147,483,648 (More)
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Asked 10/29/2011 1:41:16 AM
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