Weegy: Molecular clocks take advantage of known mutation rates to estimate how long ago organisms shared a common ancestor.
User: Suppose a population is carrying a condition controlled by two alleles: A (dominant) and a (recessive). Only homozygous individuals that have two copies of the recessive allele have the condition. If the a allele has a frequency of 20%, and the A allele had a frequency of 80%, what percentage of the population will have the condition?
A. 4%
B. 20%
C. 80%
D. 64%
(More) 8
In a population carrying a condition controlled by two alleles: A (dominant, frequency 80%) and a (recessive, frequency 20%), the percentage of the population with the condition (homozygous, aa) will be: 4%.
Working: The probability of an A sperm meeting an A egg is 0.8 x 0.8 = 0.64. The probability of an A sperm meeting an a egg is 0.8 x 0.2 = 0.16. The probability of an a sperm meeting an A egg is 0.8 x 0.2 = 0.16. The probability of an a sperm meeting an a egg is 0.2 x 0.2 = 0.04.
Added 1/16/2019 6:33:48 AM
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