**Weegy:** hen the following quadratic equation is written in general form, what is the value of "c"?
The formula of quadratic equation is
ax^2+bx+c=0
Answer: -2

**User:** The graph of y = ax 2 + bx + c passes through the points (-2, 0), (0, -2), and (2, 0). Determine the solution set of 0 = ax 2 + bx + c.
{-2}
{0}
{-2, 2}
{-2, 0, 2}

**Weegy:** The graph of y = ax^2 + bx + c passes through the points (-2, 0), (0, -2), and (2, 0). The solution set of 0 = ax 2 + bx + c is {-2, 2}

(More)8

x^2 + x - 12 = 0

x^2 + 4x - 3x - 4*3 = 0

(x + 4)(x - 3) = 0

(x + 4)(x - 3) = 0 is in factored form.

Added 11/26/2014 5:50:09 PM

This answer has been confirmed as correct and helpful.

8

The following points of (-3, 21) lies on the graph of y = x^2 - 2x + 6.

When x = -3

y = (-3)^2 - 2*(-3) + 6

y = 9 + 6 + 6

y = 9 + 12

y = 21

Added 11/26/2014 5:51:44 PM

This answer has been confirmed as correct and helpful.

8

(x - 2)(x - 3) = 2

x^2 - 2x - 3x + 6 - 2 = 0

x^2 - 4x - x + 4 = 0

(x - 1)(x - 4) = 0

(x - 1)(x - 4) = 0 is in factored form .

Added 11/26/2014 5:55:34 PM

This answer has been confirmed as correct and helpful.