Weegy: The product of (3p^4)^3 * (p^2)^7 is =27p^26
Solution:
= 3^3 (p^4)^3 * (p^2)^7
= 27 p^12 * p^14
=27p^26
User:
Find the product.
(y^2)^5 · y^8
A.y23
B.y18
C.(y)40
D.y5
Weegy: (y^2)^5 · y^8 = y^10 · y^8 = y^18
User: Find the product. If the result is negative, enter "-". If the result is positive, leave the box empty.
-7(-a^2)^2(-b^3)
User: Find the product.
(-2x^2)^3 ·3x
User:
Find the product.
(-5a^2)^3·a^5
A.-15a10
B.-125a11
C.15a6
D.-125a10
(More) 8
-7(-a^2)^2(-b^3)
= -7a^4(-b^3)
= 7a^4b^3
Added 2/28/2015 12:42:28 AM
This answer has been confirmed as correct and helpful.
Confirmed by
Andrew. [2/28/2015 12:52:37 AM]
8
(-2x^2)^3 ·3x
= -8x^6*3x
= -24x^7
Added 2/28/2015 12:43:12 AM
This answer has been confirmed as correct and helpful.
Confirmed by
Andrew. [2/28/2015 12:52:46 AM]
8
(-5a^2)^3·a^5
= -125a^6*a^5
= -125a^11
Added 2/28/2015 12:43:47 AM
This answer has been confirmed as correct and helpful.
Confirmed by
Andrew. [2/28/2015 12:53:04 AM]